Chemistry - Ideal Gas Question with Solution | TestHub
ChemistryIdeal GasGraham's Law of Diffusion/EffusionMedium2 minQB
ChemistryMediumsingle choice
According to Graham's law, at a given temperature, two gases A and B effuse through a small hole into vacuum. If P_A and P_B are their pressures and M_A and M_B their molar masses, the ratio of their rates of effusion r_A/r_B is given by:
Options:
Answer:
C
Solution:
At a given temperature, the rate of effusion of a gas through a small hole is directly proportional to its pressure and inversely proportional to the square root of its molar mass: r ∝ P/√M.
So r_A/r_B = (P_A/P_B) × √(M_B/M_A) = (P_A/P_B) × (M_B/M_A)^(1/2).
This matches option (C).
Stream:JEESubject:ChemistryTopic:Ideal GasSubtopic:Graham's Law of Diffusion/Effusion
⏱ 2mℹ️ Source: QB
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