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Chemistry - Ideal Gas Question with Solution | TestHub

ChemistryIdeal GasIdeal Gas Equation & problemsMedium2 minQB

ChemistryMediumsingle choice

The density of a gas A is twice that of a gas B at the same temperature. The molecular mass of gas $B$ is thrice that of $A$ . The ratio of the pressures acting on $A$ and $B$ will be:

Options:

Answer:

Solution:

$PM = d RT$ $d_{A} : d_{B} = 2 : 1$

$\frac{P _{A} M _{A}}{P _{B} M _{B}} = \frac{d _{A} RT}{d _{B} RT}$ $M_{A} : M_{B} = 1 : 3$

So $P_{A} : P_{B} = 6 : 1$

Stream:JEESubject:ChemistryTopic:Ideal GasSubtopic:Ideal Gas Equation & problems

⏱ 2mℹ️ Source: QB

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