Chemistry - Ideal Gas Question with Solution | TestHub

$(1)⟶(2)$

$\mathrm{PV}=\mathrm{nRT}$

${\mathrm{P}}_1=9\mathrm{atm}{\mathrm{T}}_1=303\mathrm{K}$

$P_2=T_2=404K$

For process $1⟶2$

$\frac{{\mathrm{P}}_1}{{\mathrm{P}}_2}=\frac{{\mathrm{T}}_1}{{\mathrm{T}}_2}$

${\mathrm{n}}_1$ = Initial no. of moles

$12={\mathrm{P}}_2$

$n_2=n_1$ since no. of moles have not changed.

Step (2) ⟶ Step (3)

At point 2 amount of gas increased by $50\%$.

So no. of moles $=\frac{3}{2}n$

New pressure ${\mathrm{n}}_2={\mathrm{n}}_1=\mathrm{n}$

$\frac{{\mathrm{P}}_2}{{\mathrm{P}}_3}=\frac{{\mathrm{n}}_2}{{\mathrm{n}}_3}{\mathrm{n}}_3=\frac{3}{2}\mathrm{n}$

$P_3=18atm$