Chemistry - Ideal Gas Question with Solution | TestHub
A container contains 2 moles of an ideal gas at 27°C. It is heated to 327°C. Match Column I (parameters) with Column II (increases by a factor)
Column I | Column II |
|---|---|
A) Mean free path, λ | P) 1 (at constant volume) |
B) Collision number, Z1 | Q) √(2) (at constant volume) |
C) Collision frequency, Z11 | R) 1/√(2) (at constant pressure) |
| S) 2 (at constant pressure) |
Options:
Answer:
Solution:
T doubles from 300 K to 600 K. λ = 1/(√(2)πd2(N/V)): at constant V it is unchanged, factor 1 (P); at constant P, V doubles so N/V halves and λ doubles, factor 2 (S), hence A→P,S. Z1 = √(2)πd2barv(N/V) ∝ √(T)(N/V): at constant V the factor is √(2) (Q); at constant P, N/V ∝ 1/T so Z1 ∝ √(T)/T = 1/√(T), factor 1/√(2) (R), hence B→Q,R. Z11 = (1/√(2))πd2barv(N/V)2 ∝ √(T)(N/V)2: at constant V the factor is √(2) (Q); at constant P it is √(T)/T2 = 2-3/2, not listed, so C→Q only. Hence A→P,S; B→Q,R; C→Q.
