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Chemistry - Ideal Gas Question with Solution | TestHub

ChemistryIdeal GasKinetic Theory of GasesEasy2 minPYQ_2020

ChemistryEasysingle choice

Equal masses of methane and ethane have their total translational kinetic energy in the ratio 3 : 1, then their temperatures are in the ratio is

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Answer:

Solution:

$E_{1} = \frac{3}{2} \times \frac{M}{16} R T_{1}$
$E_{2} = \frac{3}{2} \times \frac{M}{30} R T_{2}$
$\Rightarrow \frac{E_{1}}{E_{2}} = \frac{30}{16} \frac{T_{1}}{T_{2}}$
$\Rightarrow \frac{3}{1} = \frac{30}{16} \frac{T_{1}}{T_{2}}$ $\Rightarrow \frac{T_{1}}{T_{2}} = \frac{8}{5}$

Stream:NTA_ABHYASSubject:ChemistryTopic:Ideal GasSubtopic:Kinetic Theory of Gases

⏱ 2mℹ️ Source: PYQ_2020

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