Chemistry - Ideal Gas Question with Solution | TestHub

One mole of an ideal gas is subjected to a process in which $\mathrm{P}=\frac{1}{8.21}\mathrm{V}$, where P is in atm and V in litre. If the process is operating from 1 atm to finally 8 atm then the maximum temperature (in K ) is ' x ', value of $\frac{\mathrm{x}}{800}$ is $(\mathrm{R}=0.0821\mathrm{atm}-\mathrm{L}/\mathrm{mol}.\mathrm{K})$