A volume of 50 l of dry N2 is passed through 36 g of water at 300 K. After passage of gas, there is a loss of 1.20 g in water. The vapour pressure of water at 300 K is

Question

TestHub · Accepted Answer

Water carried away: n = 1.20/18 = 0.0667 mol. Treating this vapour as occupying the 50 L gas volume at partial pressure p: p = nRT/V = 0.0667 × 0.0821 × 300 / 50 = 0.0328 atm = 24.96 mm Hg. Confirms Ans: (b) 24.96 mm Hg.

Chemistry - Ideal Gas Question with Solution | TestHub

Options:

Doubts & Discussion