On a certain day the vapour pressure is 17.537 mm of Hg for water vapour in air at 300 K. The saturated vapour pressure is 20 mm. How many moles of water vapour would be required to saturate 760 litre

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On a certain day the vapour pressure is 17.537 mm of Hg for water vapour in air at 300 K. The saturated vapour pressure is 20 mm. How many moles of water vapour would be required to saturate 760 litre of air at this temperature?

TestHub · Accepted Answer

Extra pressure needed: ΔP = 20 - 17.537 = 2.463 mm = 2.463/760 atm. n = ΔP·V/RT = (2.463/760 × 760)/(0.0821 × 300) = 2.463/24.63 = 0.1 mol. Confirms Ans: (c) 0.1.

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