Chemistry - Ideal Gas Question with Solution | TestHub

ChemistryIdeal GasKinetic Theory of GasesMedium2 minQB

ChemistryMediummultiple choice

Which of the following is/are CORRECT ?

Answer:

C, D

Solution:

At constant V, n

$PT = KT^{2} \Rightarrow y = kx \Rightarrow$ Straight line

At constant P, n

$VT = KT^{2} \Rightarrow y = kx^{2} \Rightarrow$ Parabola

Slope of line (I) > Slope of line (II)

$(\frac{nR}{P})_{I} > (\frac{nR}{P})_{II}$

$∴ P_{B} > P_{A}$

At constant V & n

$P = KT$

$\frac{P}{T} = K$

$∴ \frac{P}{T} v / s T^{2}$ will be straight line.

Stream:JEESubject:ChemistryTopic:Ideal GasSubtopic:Kinetic Theory of Gases

⏱ 2mℹ️ Source: QB

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