A sample of gas has a volume of V 1 l at temperature t 1 °C. When the temperature of the gas is changed to t 2 °C at constant pressure, the volume of the gas was found to increase by 10%. The percentage increase in temperature (in °C) is

V 2 = 1.1V 1 ⇒ T 2 = 1.1T 1 , so Δ T = 0.1T 1 = 0.1(t 1 + 273). As a percentage of the Celsius temperature t 1 : (0.1(t 1 +273))/(t 1 )× 100 = 10 + 2730/(t 1 ) %. Matches (b).

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ChemistryIdeal GasIdeal Gas Equation & problemsEasy2 minQB

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A sample of gas has a volume of V₁ l at temperature t₁ °C. When the temperature of the gas is changed to t₂ °C at constant pressure, the volume of the gas was found to increase by 10%. The percentage increase in temperature (in °C) is

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Solution:

V₂ = 1.1V₁ ⇒ T₂ = 1.1T₁, so Δ T = 0.1T₁ = 0.1(t₁ + 273). As a percentage of the Celsius temperature t₁: (0.1(t₁+273))/(t₁)× 100 = 10 + 2730/(t₁) %. Matches (b).

Stream:JEESubject:ChemistryTopic:Ideal GasSubtopic:Ideal Gas Equation & problems

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