Chemistry - Ideal Gas Question with Solution | TestHub
A 60 litre vessel is equally divided into three chambers with the help of two stationary (fixed) semi-permeable membranes (SPM). The vessel contains 48 g H₂ in the left chamber, 192 g O₂ in the middle chamber and 112 g N₂ in the right chamber. The left SPM allows transfer of only H₂ gas while the right SPM allows the transfer of both H₂ and N₂. If the ratio of final total pressures in the three chambers is x:y:5, then the value of (5 x x x y) is
Answer:
Solution:
Each chamber has volume V = 20 L. Moles: n(H₂) = 48/2 = 24, n(O₂) = 192/32 = 6, n(N₂) = 112/28 = 4. At equilibrium: H₂ crosses both SPMs and fills all 60 L: p(H₂) = 24RT/60 = 0.4 RT. N₂ crosses only the right SPM, occupying middle + right (40 L): p(N₂) = 4RT/40 = 0.1 RT. O₂ stays in the middle: p(O₂) = 6RT/20 = 0.3 RT. Total pressures: left = 0.4 RT; middle = 0.4 + 0.3 + 0.1 = 0.8 RT; right = 0.4 + 0.1 = 0.5 RT. Ratio 0.4 : 0.8 : 0.5 = 4 : 8 : 5, so x = 4, y = 8 and 5xy = 5 × 4 × 8 = 160. Hence the answer is 0160.
