Chemistry - Ideal Gas Question with Solution | TestHub
ChemistryIdeal GasGraham's Law of Diffusion/EffusionMedium2 minQB
ChemistryMediumsingle choice
Passage / Comprehension
The leak rate, -dp/dt, of a gas is directly proportional to the difference in pressure of the gas in the cylinder and the external pressure. Some ideal gas is taken in a cylinder of 10 l capacity at 20 atm and 300 K. The proportionality constant is k = 10-3 s-1. The constant external pressure is 1 atm. (ln 38 = 3.6, ln 2 = 0.7, ln 10 = 2.3)
What is the pressure of gas in the cylinder after 1 h?
Options:
Answer:
C
Solution:
The leak law is -dp/dt = k(p - pext) with k = 10-3 s-1 and pext = 1 atm. Integrating, p - 1 = (p0 - 1)e-kt = 19e-kt. After t = 1 h = 3600 s, kt = 3.6: p - 1 = 19e-3.6 = 19/38 = 0.5 atm, so p = 1.5 atm. Hence Ans (c).
Stream:JEESubject:ChemistryTopic:Ideal GasSubtopic:Graham's Law of Diffusion/Effusion
⏱ 2mℹ️ Source: QB
Doubts & Discussion
Loading discussions...
