A 4.0 l box contains 29.0 g of a mixture of gases CₓH₆ and CₓH₁₀. The pressure of the gas mixture at 300 K is 3.08 atm. The analysis of the gas mixture shows that carbon is 82.8%, by mass. The value o

Question

A 4.0 l box contains 29.0 g of a mixture of gases CₓH₆ and CₓH₁₀. The pressure of the gas mixture at 300 K is 3.08 atm. The analysis of the gas mixture shows that carbon is 82.8%, by mass. The value of x is

TestHub · Accepted Answer

Total moles n = PV/RT = 3.08 × 4.0/(0.0821 × 300) = 0.50 mol.

Average molar mass = 29.0/0.50 = 58.0 g/mol.

Carbon mass per mole of mixture = 12x, so 12x/58.0 = 0.828 ⇒ 12x = 48 ⇒ x = 4. (Mixture of C₄H₆ and C₄H₁₀.)

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