Chemistry - Ideal Gas Question with Solution | TestHub

ChemistryIdeal GasGraham's Law of Diffusion/EffusionMedium2 minQB

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Passage / Comprehension

The constant motion and high velocities of gas particles lead to some important practical consequences. One such consequence is that as minimum rapidly when they come in contact. The mixing of different gases by random molecular motion and with frequent collisions is called diffusion A similar process in which gas molecules escape through a tiny hole into a vaccume is called effusion.

For 10 min . each at $2 7^{\circ} C$ , from two identical bulbs helium and an unknown gas X at equal pressures are leaked into a common vessel of 3 L capacity. The resulting pressure is 4.1 atm and the mixture contains 0.4 mol of helium. The molar mass of gas X is :

Options:

Answer:

Solution:

$P_{T} V = n RT$

$n He X \frac{4}{1} = \frac{4.1}{0.0821 \times 300} = 0.5 = 0.4 m o l e = 0.1 m o l e = \frac{r _{He}}{r _{X}} = \frac{M _{X}}{M _{He}} \Rightarrow M_{X} = 6.4$

Stream:JEESubject:ChemistryTopic:Ideal GasSubtopic:Graham's Law of Diffusion/Effusion

⏱ 2mℹ️ Source: QB

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