Chemistry - Ideal Gas Question with Solution | TestHub
ChemistryIdeal GasKinetic Theory of GasesHard2 minQB
ChemistryHardnumerical
An argon atom is released from the surface of the earth to travel upwards at 300 K. Assuming that it undergoes no collisions with other molecules, how long (in meter) will it travel before coming to rest? (Atomic mass of Ar = 40, g = 10 ms-2, R = 8.4 J/K-mol)
Answer:
9450.00
Solution:
Take the atom's upward speed as the rms speed at 300 K: vrms = √(3RT/M) = √(3 × 8.4 × 300/0.040) = √(189000) = 434.7 m/s. Rising against gravity, it stops when the kinetic energy is converted to potential energy: (1/2)mv2 = mgh, so h = v2/(2g) = 189000/(2 × 10) = 9450 m. Hence the distance travelled is 9450 m.
Stream:JEESubject:ChemistryTopic:Ideal GasSubtopic:Kinetic Theory of Gases
⏱ 2mℹ️ Source: QB
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