An ideal gas, Yₙ, is taken in a container connected to a frictionless, massless piston. The pressure of the gas is constant (always equal to the atmospheric pressure). The expected graph for the varia

Question

An ideal gas, Yₙ, is taken in a container connected to a frictionless, massless piston. The pressure of the gas is constant (always equal to the atmospheric pressure). The expected graph for the variation of volume of gas with temperature was to be like fig. I, but the actual graph is like fig. II. The deviation was attributed to dissociation of gas as: Yₙ(g) → n Y(g). If the yield of this reaction is only 50%, the value of n is

TestHub · Accepted Answer

At constant pressure the slope dV/dt is proportional to the total moles of gas particles.

Expected slope: (40.0 - 39.7)/20 = 0.3/20; actual slope: (38.8 - 37.9)/20 = 0.9/20.

Ratio = 0.9/0.3 = 3 = 1 + alpha(n - 1), alpha = 0.50.

1 + 0.5(n - 1) = 3 ⇒ n - 1 = 4 ⇒ n = 5.

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