Chemistry - Ideal Gas Question with Solution | TestHub

ChemistryIdeal GasMiscellaneous/MixedEasy2 minPYQ_2020

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What will be the relation between the $T_{1}$ of gas 1 with $M_{1} = 56$ and $T_{2}$ of gas 2 with $M_{2} = 44$ if the average speed of gas 1 is equal to most probable speed of gas 2?

Options:

Answer:

Solution:

$c_{a v} = \sqrt{\frac{8 R T}{π M}}; c_{m p} = \sqrt{\frac{2 R T}{M}}$

Given that, $\sqrt{\frac{8 R T_{1}}{π M_{1}}} = \sqrt{\frac{2 R T_{2}}{M_{2}}}$

$\frac{8 T_{1}}{π M_{1}} = \frac{2 T_{2}}{M_{2}}$

$\frac{4 T_{1}}{π \times 56} = \frac{T_{2}}{44}$

$\frac{T_{1}}{T_{2}} = \frac{56 \times π}{44 \times 4} = 1$

$T_{1} = T_{2}$

Stream:NTA_ABHYASSubject:ChemistryTopic:Ideal GasSubtopic:Miscellaneous/Mixed

⏱ 2mℹ️ Source: PYQ_2020

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