Chemistry - Ideal Gas Question with Solution | TestHub
ChemistryIdeal GasKinetic Theory of GasesEasy2 minQB
ChemistryEasysingle choice
At what temperature does the average translational KE of a molecule in a gas becomes equal to the K.E. of an electron accelerated through a PD of 6 V?
Options:
Answer:
C
Solution:
Electron KE = eV = (1.6×10⁻¹⁹)(6) = 9.6×10⁻¹⁹ J. Set 3/2kT = 9.6×10⁻¹⁹: T = (2 × 9.6×10⁻¹⁹)/3 × 1.38×10⁻²³ ≈ 4.64×10⁴ K = 46,400 K. Confirms Ans (c).
Stream:JEESubject:ChemistryTopic:Ideal GasSubtopic:Kinetic Theory of Gases
⏱ 2mℹ️ Source: QB
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