Start Free Mock LoginAlready registered? Login here

Chemistry - Ideal Gas Question with Solution | TestHub

ChemistryIdeal GasMiscellaneous/MixedEasy2 minPYQ_2020

ChemistryEasysingle choice

A gaseous mixture containing $H e, C H_{4}$ and $S O_{2}$ was allowed to effuse through a fine hole then find what molar ratio of gases coming out initially? (Given mixture contains $H e, C H_{4}$ and $S O_{2}$ in 1 : 2 : 3 mole ratio)

Options:

Answer:

Solution:

$\frac{{n^{}}_{H e}^{}}{{n^{}}^{}_{C H}^{}_{4}} = \frac{1}{2} \sqrt{\frac{16}{4}} = \frac{1}{1}$

$\frac{{n^{}}_{H e}^{}}{{n^{}}^{}_{S O}^{}_{2}} = \frac{1}{3} \sqrt{\frac{64}{4}} = \frac{4}{3}$

So, $n_{He} : n_{{CH}_{4}} : n_{{SO}_{2}} = 4 : 4 : 3$

Stream:NTA_ABHYAS_NEETSubject:ChemistryTopic:Ideal GasSubtopic:Miscellaneous/Mixed

⏱ 2mℹ️ Source: PYQ_2020

Doubts & Discussion

Loading discussions...