To an evacuated vessel with movable piston under external pressure of 1 atm , 0.1 mole of He and 1.0 mole of an unknown compound (vapour pressure 0.68 ma t h r m a t m at 0 ∘ C ) are introduced. Consi

Question

To an evacuated vessel with movable piston under external pressure of 1 atm , 0.1 mole of He and 1.0 mole of an unknown compound (vapour pressure 0.68 ma t h r m a t m at 0 ∘ C ) are introduced. Considering the ideal gas behaviour, the total volume (in litre) of the gases at 0 ∘ C is close to

TestHub · Accepted Answer

Since, the external pressure is 1.0 atm , the gas pressure is also 1.0 atm as piston is movable. Out of this 1.0 atm partial pressure due to unknown compound is 0.68 atm . Therefore, partial pressure of He = 1.00 − 0.68 = 0.32 atm . ​ ⇒ Volume = r ( He ) n ( He ) RT ​ = 0.32 0.1 × 0.082 × 273 ​ = 7 L ⇒ Volume of container = Volume of He . ​

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