When isobutane is monochlorinated in the presence of ultra-violet light, the product obtained in higher yield is

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TestHub · Accepted Answer

CH₃–CH(CH₃)–CH₃ + Cl₂/hν → CH₃–CH(CH₃)–CH₂Cl + CH₃–C(CH₃)₂Cl

therefore:

$\frac{I so b u t y l c h l or i d e}{t er t - B u t y l c h l or i d e} = \frac{N u mb ero f 1° H \times R e a c t i v i t yo f 1° H}{N u mb ero f 3° H \times R e a c t i v i t yo f 3° H} = \frac{9 \times 1}{1 \times 5} = \frac{9}{5}$

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