Chemistry - Hydrocarbon Question with Solution | TestHub

Here X is${\text{CH}}_3-\text{C}\equiv \stackrel{-}{\text{C}}\stackrel{\oplus }{\text{N}}\text{a}$which is formed as follows
$\text{Br}-{\text{CH}}_2-\text{CH}={\text{CH}}_2\stackrel{\stackrel{-}{\text{N}}{\text{H}}_2}{\to }\left[{\text{CH}}_2=\text{C}={\text{CH}}_2\right]\stackrel{\text{Rearrangement}}{\to }\left[{\text{CH}}_3-\text{C}\equiv \text{CH}\right]\stackrel{{\text{NaNH}}_2}{\to }{\text{CH}}_3-\text{C}\equiv \stackrel{-}{\text{C}}\stackrel{\oplus }{\text{N}}\text{a}$