Heating of 2-chloro-1-phenylbutane with E t O K / E t O H gives X as the major product. Reaction X with H g ( O A c ) 2 / H 2 O followed by N a B H 4 gives Y as the major product. Y is:

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EtOK is potassium ethylene oxide and it is colourless gas and is liquid at low temperatures and is highly flammable i.e. that catches fire easily and undergoes alkylation reactions with many organic compounds and EtOH is the ethanol.

The heating of 2-chloro-1-phenylbutane with $EtOK / EtOH$ gives X as the major product. Reaction X with H $g {(OAc)}_{2} / H_{2} O$ followed by ${NaBH}_{4}$ gives Y as the major product. Y is 1-phenylbutanol.

Chemistry - Hydrocarbon Question with Solution | TestHub

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