The given reaction is C H 3 - C H = C H - C H 2 O H → H B r C H 3 - C H | B r - C H = C H 2

It is a case of S N 1 reaction in which O H - is substituted by B r - as follows C H 3 - C H = C H - C H 2 O H → H ⊕ C H 3 - C H = C H - C ⊕ H 2 ↔ C H 3 - C ⊕ H - C H = C H 2 → B r - C H 3 - C | H B r - C H = C H 2

Chemistry - Halogen Derivative Question with Solution | TestHub

ChemistryHalogen DerivativeNUCLEOPHILIC SUBSTITUTION REACTIONS (SN1 AND SN2), SN(NEIGHBOURING GROUP PARTICIPATION), SNIEasy2 minPYQ_2020

ChemistryEasysingle choice

The given reaction is
$C H_{3} - C H = C H - C H_{2} O H \overset{H B r}{\to} C H_{3} - \overset{B r}{\overset{|}{C H}} - C H = C H_{2}$

Options:

Answer:

Solution:

It is a case of $S_{N} 1$ reaction in which $O H^{-}$ is substituted by $B r^{-}$ as follows
$C H_{3} - C H = C H - C H_{2} O H \overset{\overset{\oplus}{H}}{\to} C H_{3} - C H = C H - \overset{\oplus}{C} H_{2} \leftrightarrow C H_{3} - \overset{\oplus}{C} H - C H = C H_{2} \overset{\bar{B r}}{\to} C H_{3} - \underset{B r}{\underset{|}{C} H} - C H = C H_{2}$

Stream:NTA_ABHYAS_NEETSubject:ChemistryTopic:Halogen DerivativeSubtopic:NUCLEOPHILIC SUBSTITUTION REACTIONS (SN1 AND SN2), SN(NEIGHBOURING GROUP PARTICIPATION), SNI

⏱ 2mℹ️ Source: PYQ_2020

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