Chemistry - Halogen Derivative Question with Solution | TestHub

The hydrocarbon of mass 72 is${\mathrm{C}}_5{\mathrm{H}}_{12}$. Since there is one monoclhoro derivative, the compound has twelve equivalent H's in four equivalent$\mathrm{C}{\mathrm{H}}_3\mathrm{\prime }\mathrm{s}$. The compound is$(\mathrm{C}{\mathrm{H}}_3{)}_4\mathrm{C}$(2,2-dimethylpropane) and the chloro derivative are as follows