In the reaction sequence CH 3 − CH 2 − CH 2 − Br → AgCN X → H 2 O / OH − Y (Y) will be

Here X is propyl isocyanide and Y is propyl amine C H 3 - C H 2 - C H 2 - B r → A g C N C H 3 - C H 2 - C H 2 - N ⊕ ≡ C - ( X ) → H 2 O / O - H / Δ C H 3 - C H 2 - C H 2 - N H 2 ( Y ) + H C O O H

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Chemistry - Halogen Derivative Question with Solution | TestHub

ChemistryHalogen DerivativeNUCLEOPHILIC SUBSTITUTION REACTIONS (SN1 AND SN2), SN(NEIGHBOURING GROUP PARTICIPATION), SNIEasy2 minPYQ_2020

ChemistryEasysingle choice

In the reaction sequence
${CH}_{3} - {CH}_{2} - {CH}_{2} - Br \overset{AgCN}{\to} (X) \overset{H_{2} O / {OH}^{-}}{\to} (Y)$
(Y) will be

Options:

Answer:

Solution:

Here X is propyl isocyanide and Y is propyl amine
$C H_{3} - C H_{2} - C H_{2} - B r \overset{A g C N}{\to} \underset{(X)}{C H_{3} - C H_{2} - C H_{2} - \overset{\oplus}{N} \equiv \bar{C}} \overset{H_{2} O / \bar{O} H / Δ}{\to} \underset{(Y)}{C H_{3} - C H_{2} - C H_{2} - N H_{2}} + H C O O H$

Stream:NTA_ABHYAS_NEETSubject:ChemistryTopic:Halogen DerivativeSubtopic:NUCLEOPHILIC SUBSTITUTION REACTIONS (SN1 AND SN2), SN(NEIGHBOURING GROUP PARTICIPATION), SNI

⏱ 2mℹ️ Source: PYQ_2020

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