Chemistry - GOC Question with Solution | TestHub

A strong amide base removes a terminal-alkyne proton to form acetylide; ammonia is a weaker acid and can escape, so A favours the right. Phenol is more acidic than water, so hydroxide forms phenoxide: B favours the right. The alcohol groups of the diol in C are not acidic enough to liberate CO₂ with bicarbonate. Aqueous NaOH does not appreciably convert ethanol to ethoxide because water competes as an acid. Thus A,B.