Find the number of compounds which are less basic than aniline.
(i) (ii) (iii) (iv)
(v) (vi) (vii) (viii) $N H_{3}$
(ix) (x) $C H_{3} - C \equiv N$

Question

Find the number of compounds which are less basic than aniline. (i) (ii) (iii) (iv) (v) (vi) (vii) (viii) N H 3 ​ (ix) (x) C H 3 ​ − C ≡ N

TestHub · Accepted Answer

Aniline: p K a ​ H = 4.6. (i) 4-methylaniline (5.1): more basic. (ii) 4-nitroaniline (1.0): less. (iii) benzylamine (9.3): more. (iv) N-methylaniline (4.9): more. (v) pyridine (5.2): more. (vi) pyrrole (lone pair in the aromatic sextet): less. (vii) acetanilide (lone pair delocalised into C = O ): less. (viii) N H 3 ​ (9.3): more. (ix) diphenylamine (0.8): less. (x) C H 3 ​ CN (sp nitrogen): less. Less basic: (ii), (vi), (vii), (ix), (x) = 5. Answer: 5.

Chemistry - GOC Question with Solution | TestHub

Doubts & Discussion