Predict the direction of the following equilibrium and the approximate value of Keq.
HCN + $C H_{3} CO O^{-}$ $⇌$ $C N^{-}$ + $C H_{3} COOH$ ( $p K_{a}$ : HCN = 9.2, $C H_{3} COOH$ = 4.76)

Question

Predict the direction of the following equilibrium and the approximate value of Keq. HCN + C H 3 ​ CO O − ⇌ C N − + C H 3 ​ COOH ( p K a ​ : HCN = 9.2, C H 3 ​ COOH = 4.76)

TestHub · Accepted Answer

The acid on the left is HCN ( p K a ​ 9.2) and the acid on the right is C H 3 ​ COOH ( p K a ​ 4.76). HCN is the weaker acid, so the equilibrium lies to the left : acetate is not basic enough to deprotonate HCN completely. Keq ≈ 1 0 4 ⋅ 76 − 9 ⋅ 2 = 1 0 − 4 ⋅ 44 ⋅

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