Chemistry - GOC Question with Solution | TestHub
ChemistryGOCAcid BaseHard2 minQB
ChemistryHardnumerical
Carbon-14 labelled acetic acid, CH₃-¹⁴C(=O)-OH, is treated separately with two reagents.
CH₃¹⁴COOH + NaH salt + gas A
CH₃¹⁴COOH + NaNH₂ salt + gas B
If X is the sum of the molar masses of A and B, find the value of X - 15.
Answer:
4.00
Solution:
With NaH the acid releases hydrogen : gas A = H₂, molar mass 2. With NaNH₂ it releases ammonia : gas B = NH₃, molar mass 17. The ¹⁴C label stays behind in the carboxylate salt and does not enter either gas. X - 15 = 2 + 17 - 15 = 4.
Stream:JEESubject:ChemistryTopic:GOCSubtopic:Acid Base
⏱ 2mℹ️ Source: QB
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