Chemistry - GOC Question with Solution | TestHub

Benzylamine has an available nitrogen lone pair because ${\mathrm{CH}}_2$ separates it from the benzene ring. In $\mathrm{N}$-methylaniline that lone pair is conjugated with the ring, the nitro group further weakens the aniline base, and an amide lone pair is delocalized into $\mathrm{C}=\mathrm{O}$. Hence benzylamine is strongest.