Chemistry - GOC Question with Solution | TestHub

ChemistryGOCRESONANCE AND MESOMERIC EFFECTMedium2 minQB
ChemistryMediumnumerical
Passage / Comprehension

When a base abstract H bonded to carbon, carbanion is formed

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Carbon bearing negative charge is sp3 hybridised, undergo fluxional inversion.

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Consider the following reaction-

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A carbanion is formed in the first step of above reaction which finally gives the desired product. Which is the most likely position of carbanion responsible for the above reaction is ______?

Answer:
2.00
Solution:

OH⁻ first abstracts the most acidic α-hydrogen adjacent to the carbonyl group.

Removal of H from position 2 forms a resonance-stabilized enolate (carbanion).

This carbanion is stabilized by conjugation with the C=O group, making it the most favorable intermediate.

The enolate then attacks the double bond intramolecularly, leading to ring closure.

Finally, elimination of Br⁻ and rearrangement gives the fused cyclic product shown.

Therefore, the carbanion is formed at position 2, so the correct answer is 2.

Stream:JEESubject:ChemistryTopic:GOCSubtopic:RESONANCE AND MESOMERIC EFFECT
2mℹ️ Source: QB

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