Chemistry - GOC Question with Solution | TestHub

Because acidic character $\propto$ stability of conjugate base (Anion)

(a) $\mathrm{CH}=\stackrel{-}{\mathrm{C}}\text{anion}(-\text{ve on }{\mathrm{C}}_{\mathrm{sp}})$

(b) ${\mathrm{CH}}_3-\mathrm{C}\equiv \stackrel{-}{\mathrm{C}}(-\text{ve on }{\mathrm{C}}_{\mathrm{sp}}\text{ and }+\mathrm{I}\text{ of }-{\mathrm{CH}}_3)$

(c) ${\mathrm{CH}}_2=\stackrel{-}{\mathrm{C}}\mathrm{H}(-\text{ve on }{\mathrm{C}}_{{\mathrm{sp}}^2})$

Acidic character order $\underset{{\mathrm{C}}_{\mathrm{sp}}}{\mathrm{CH}\equiv \stackrel{-}{\mathrm{C}}}>\underset{{\mathrm{C}}_{\mathrm{sp}}\text{with}+\mathrm{I}\text{ of }{\mathrm{CH}}_3}{{\mathrm{CH}}_3-\mathrm{C}\equiv \stackrel{-}{\mathrm{C}}}>\underset{{\mathrm{C}}_{{\mathrm{sp}}^2}}{{\mathrm{CH}}_2=\stackrel{-}{\mathrm{C}}}$