Imagine a universe in which principal quantum number have same possible value as in our universe except angular quantum number ( ℓ ) can have value from [ 0 , 1 , 2 , …… n + 1 ] . Magnetic quantum num

Question

Imagine a universe in which principal quantum number have same possible value as in our universe except angular quantum number $(ℓ)$ can have value from $[0, 1, 2, \dots\dots n + 1]$ .

Magnetic quantum number (m) can have value from [–(ℓ + 1) to + (ℓ + 1)] [including zero]

Spin quantum number (m_s ) can have value = $[- \frac{1}{2}, 0, + \frac{1}{2}]$

Now find the maximum number of electron that can be filled in 2^nd period.

TestHub · Accepted Answer

For the 2 n d period in this imaginary universe, we follow the Aufbau principle where orbitals are filled in increasing order of ( n + ℓ ) . A period starts with the filling of a new shell's s -orbital ( ℓ = 0 ) and ends right before the next shell's s -orbital begins. 1st Period: Fills orbitals with ( n + ℓ ) < 2 and ( 1 , 1 ) before ( 2 , 0 ) starts → ( 1 , 0 ) and ( 1 , 1 ) . 2nd Period: Starts with ( 2 , 0 ) and includes all remaining orbitals before ( 3 , 0 ) starts → ( 2 , 0 ) , ( 1 , 2 ) , and ( 2 , 1 ) . Using the given rules, the number of values for m (orbitals) is 2 ( ℓ + 1 ) + 1 = 2 ℓ + 3 , and each orbital holds 3 electrons (since m s ​ has 3 values): O r bi t a l s f or ( 2 , 0 ) = 2 ( 0 ) + 3 = 3 O r bi t a l s f or ( 1 , 2 ) = 2 ( 2 ) + 3 = 7 O r bi t a l s f or ( 2 , 1 ) = 2 ( 1 ) + 3 = 5 T o t a lEl ec t ro n s = ( 3 + 7 + 5 ) × 3 = 15 × 3 = 45

Chemistry - GENERAL CHEMISTRY Question with Solution | TestHub

Doubts & Discussion