Chemistry - GENERAL CHEMISTRY Question with Solution | TestHub

The electronic configuration can be written as,

$1{\mathrm{s}}^2, 2{\mathrm{s}}^2, 2{\mathrm{p}}^6, 3{\mathrm{s}}^2, 3{\mathrm{p}}^6, 4{\mathrm{s}}^2, 3{\mathrm{d}}^{10}, 4{\mathrm{p}}^6, 5{\mathrm{s}}^1$

The outermost electron has i.e.,${}_{36}{}^{}\left[\mathrm{Kr}\right]5{\mathrm{s}}^1$

Principal quantum number$=5$

Azimuthal quantum number$=0$(corresponds to s)

Magnetic quantum number$=0$

Spin quantum number$=+\frac{1}{2}$(positive spin)