( NH 4 ) 2 BeF 4 Δ A ( gas ) + B + HF BeO ( s ) + C ( s ) + C l 2 ( g ) Δ D ( gas ) + E Hybridisation of central atom in B involves "x" number of orbitals and hybridisation of so called ce

Question

( NH 4 ​ ) 2 ​ BeF 4 ​ Δ ​ A ( gas ) + B + HF BeO ( s ) + C ( s ) + C l 2 ​ ( g ) Δ ​ D ( gas ) + E Hybridisation of central atom in B involves "x" number of orbitals and hybridisation of so called central atom in dimer of E involves "y" number of orbitals, then (x + y) is______

TestHub · Accepted Answer

Reaction 1: Thermal decomposition gives $(N H_{4})_{2} B e F_{4} Δ 2 N H_{3} (g) + Be F_{2} + 2 H F$ , identifying compound B as $B e F_{2}$ .

Value of $x$ : The central Be atom in monomeric $B e F_{2}$ is sp hybridized, which involves $x = 2$ orbitals (s and p).

Reaction 2: The chlorination reaction is $B e O + C + C l_{2} Δ CO (g) + BeC l_{2}$ , identifying compound E as $B e C l_{2}$ .

Value of $y$ : In the dimer state $B e_{2} C l_{4}$ , each Be atom forms 3 bonds (via chloro-bridges) and is sp² hybridized, involving $y = 3$ orbitals.

Final Answer: Therefore, the value of $x + y = 2 + 3 = 5.00$ .

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