Chemistry - GENERAL CHEMISTRY Question with Solution | TestHub

For$\text{n=5}$$\text{5s,}\text{5p,}\text{5d,}\text{5f}$and$5\text{g}$and subshell is available

In$5\text{s}\to 1\text{orbital}$

$5\text{p}\to 3\text{orbital}$

$\text{5d}\to \text{5 orbital}$

$\text{5f}\to \text{7}\text{orbital}$

$5\text{g}\to \text{9}\text{orbital}$

In each subshell 1 electron of every orbital will belong to$m_5=+\frac{1}{2}$So, Total number of orbitals that will be associate with$m_5=+\frac{1}{2}$will be$1+3+5+7+9=25$