Chemistry - GENERAL CHEMISTRY Question with Solution | TestHub

(P) $[\mathrm{Xe}]6{\mathrm{s}}^2,4{\mathrm{f}}^{14},5{\mathrm{d}}^{10},6{\mathrm{p}}^2$ → (4)

• This is a heavy element (like Pb)
• It has many inner electrons → maximum shielding effect
• Hence, matches with (4) maximum number of low shielding electrons

(Q) )$[\mathrm{Ar}]4{\mathrm{s}}^1$→ (2), (3)

• Element is K (Potassium) → belongs to 4th period
• After removing 1 electron → becomes [Ar] (stable, no unpaired e⁻) → diamagnetic

(R) $[\mathrm{Ne}]3{\mathrm{s}}^{2}3{\mathrm{p}}^1$ → (1), (2)

• Element is Al (Aluminium)
• After removing 3 electrons → reaches stable noble gas → big jump after 3rd IE
• Removing 1 electron makes it more stable → diamagnetic tendency

(S) )$[\mathrm{Ar}]4{\mathrm{s}}^{2}3{\mathrm{d}}^1$ → (1), (3)

• Element is Sc (Scandium) → 4th period
• After removing 3 electrons → stable core → sudden jump after 3rd IE