If energy order of subshells is defined according to ( n − ℓ ) rule instead of ( n + ℓ ) rule, then total number of orbitals between 1s and 2s subshell would be -(If ( n − ℓ ) same, then subshell havi

Question

If energy order of subshells is defined according to ( n − ℓ ) rule instead of ( n + ℓ ) rule, then total number of orbitals between 1s and 2s subshell would be -(If ( n − ℓ ) same, then subshell having lower ' n ' will be consider as lower in energy) [consider that system have only first four shells] - [If your answer is greater than 9, add all digits]

TestHub · Accepted Answer

Calculate ( n − ℓ ) values for all subshells up to n = 4 : n − ℓ = 1 : 1 s ( 1 − 0 = 1 ) , 2 p ( 2 − 1 = 1 ) , 3 d ( 3 − 2 = 1 ) , 4 f ( 4 − 3 = 1 ) n − ℓ = 2 : 2 s ( 2 − 0 = 2 ) , 3 p ( 3 − 1 = 2 ) , 4 d ( 4 − 2 = 2 ) Arrange by energy order (lower ( n − ℓ ) first; for ties, lower n has lower energy): 1 s < 2 p < 3 d < 4 f < 2 s < 3 p < 4 d Identify subshells between 1 s and 2 s : These are 2 p , 3 d , and 4 f . Count total orbitals: 3 ( f ro m 2 p ) + 5 ( f ro m 3 d ) + 7 ( f ro m 4 f ) = 15orbitals . Sum the digits (since 15 > 9 ): 1 + 5 = 6

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