Start Free Mock LoginAlready registered? Login here

Chemistry - GENERAL CHEMISTRY Question with Solution | TestHub

ChemistryGENERAL CHEMISTRYElectronic ConfigurationMedium2 minQB

ChemistryMediuminteger

Consider Palladium (Pd) and its electronic configuration

Number of unpaired electrons = x

Number of empty orbitals in outermost occupied shell = y

Number of completely filled orbitals having n – ℓ > 1 = z

Calculate value of x + y + z

Answer:

Solution:

Pd: [Kr] $4 d^{10}$ . $x = 0$ (no unpaired electrons). $y = 0$ (no empty $4 d$ or $5 s$ ). $z = 21$ (all filled orbitals with $n - ℓ > 1$ ). $x + y + z = 0 + 0 + 21 = 21$ .

Stream:JEESubject:ChemistryTopic:GENERAL CHEMISTRYSubtopic:Electronic Configuration

⏱ 2mℹ️ Source: QB

Doubts & Discussion

Loading discussions...