Elements P & Q are from 3 rd & 4 th period respectively. Atom of element P is paramagnetic in ground state and atom of element Q is diamagnetic in ground state. IF "P" is a p-block element & Q is from

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Elements P & Q are from 3 rd & 4 th period respectively. Atom of element P is paramagnetic in ground state and atom of element Q is diamagnetic in ground state. IF "P" is a p-block element & Q is from 'd'-block and "P" forms a T shape compound with Fluorine. Then

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P is Chlorine (Cl) because it is a 3rd-period p-block element ( $1 s^{2} 2 s^{2} 2 p^{6} 3 s^{2} 3 p^{5}$ ) that is paramagnetic and forms a T-shaped molecule (ClF₃).

Q is Zinc (Zn) since it is a 4th-period d-block element ( $1 s^{2} 2 s^{2} 2 p^{6} 3 s^{2} 3 p^{6} 3 d^{10} 4 s^{2}$ ) that is completely paired (diamagnetic).

For Chlorine, the $l = 1$ (p) subshells contain $2 p^{6}$ (3 spin-up, 3 spin-down) and $3 p^{5}$ (3 spin-up, 2 spin-down) electrons.

The number of exchange pairs is calculated as:

$(^{3} C_{2} +^{3} C_{2})_{f or 2 p} + (^{3} C_{2} +^{2} C_{2})_{f or 3 p} = (3 + 3) + (3 + 1) = 10$

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