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Chemistryf-blockf-blockMedium2 minQB
ChemistryMediuminteger

The number of radioactive elements among lanthanides and actinide

The number of Lanthanides element have greater radius than "Eu" = b

The number of actinides which show +6 oxidation state = c 

(Fill your answer as sum of digits till you get the single digit answer)

Answer:
2
Solution:

Question Explanation:

Find the sum of radioactive f-block elements (a), lanthanides larger than Europium (b), and actinides with a + 6 oxidation state (c), reducing the total to a single digit. Concept:

Radioactivity: Pm(1)+ all Actinides (15).

Atomic Radius: Eu is the largest lanthanide due to its metallic bonding nature. Oxidation States: U, Np, Pu, Am exhibit +6 states.

Solution:

a =16 (1 lanthanide +15 actinides)

b =0 (Europium is the maximum)

c =4(U, Np, Pu, Am)

Total =16 + 0 + 4 = 20

Single Digit Sum = 2 + 0 = 2

Final Answer: 2

Stream:JEESubject:ChemistryTopic:f-blockSubtopic:f-block
2mℹ️ Source: QB

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