Chemistry - f-block Question with Solution | TestHub

+4 oxidation state of cerium is also known in solutions.
${\text{4f}}^{\text{1}}{\text{5d}}^{\text{0}}{\text{6s}}^{\text{0}}\text{:}{\text{Ce}}^{\text{+3}}$
${\text{4f}}^{\text{0}}{\text{5d}}^{\text{0}}{\text{6s}}^{\text{0}}\text{:}{\text{Ce}}^{\text{+4}}$
The high charge on${\text{Ce}}^{\text{4+}}$leads to high hydration, hydrated${\text{Ce}}^{\text{4+}}$is hydrolysed giving polymeric species and${\text{H}}^{+}$.$\text{Ce}\left(\text{+4}\right)$is stable in strongly acidic solutions and used as oxidising agent in volumetric analysis.