Chemistry - Eudiometry Question with Solution | TestHub

ChemistryEudiometryDetermination of Molecular FormulaMedium2 minQB

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20 mL of a gaseous hydrocarbon was exploded with 120 mL of oxygen. A contraction of 60 mL was observed, and a further contraction of 60 mL took place when KOH was added. What is the formula of the hydrocarbon :

Options:

Answer:

Solution:

$C_{x} H_{γ} + (x + y /4) O_{2} \to XC O_{2} + \frac{y}{2} H_{2} O$

$t = 020120 t = f t 0120 - 20 (x + \frac{y}{4}) 20 x = 60 V_{i} - V_{f} = 60 y = 8$

Stream:JEESubject:ChemistryTopic:EudiometrySubtopic:Determination of Molecular Formula

⏱ 2mℹ️ Source: QB

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