Chemistry - Eudiometry Question with Solution | TestHub

ChemistryEudiometryDetermination of Molecular FormulaMedium2 minQB

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A 2L sample of a gaseous hydrocarbon is burnt in excess oxygen. The only products of the reaction are 8 L of $CO_{2} (g)$ and 10 L of $H_{2} O (g)$ , all at $10 0^{\circ} C$ and 1 atm pressure. The molecular formula of the hydrocarbon is -

Options:

Answer:

Solution:

$C_{x} H_{y} + (x + \frac{y}{4}) O_{2} \to x CO_{2} + \frac{y}{2} H_{2} O$

From the problem statement, we have:

$2 L \to 8 L \Rightarrow x = \frac{8}{2} = 4$

Also, the ratio of $x$ to $y /2$ is $8 : 10$ , which implies:

$x : \frac{y}{2} = 8 : 10$

Substituting $x = 4$ :

$4 : \frac{y}{2} = 8 : 10$

$\frac{4}{y /2} = \frac{8}{10}$

$\frac{8}{y} = \frac{8}{10}$

$y = 10$

Therefore, the chemical formula is $C_{4} H_{10}$ .

Stream:JEESubject:ChemistryTopic:EudiometrySubtopic:Determination of Molecular Formula

⏱ 2mℹ️ Source: QB

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