Chemistry - Eudiometry Question with Solution | TestHub

Question Explanation: This is a context-dependent question that seems to analyze a combustion reaction from a previous problem description.

Concept: Limiting Reactant.

Solution: To identify the incorrect statement about a reaction, we first need to identify the limiting reagent. The limiting reagent is the reactant that is completely consumed and determines the maximum amount of product that can be formed. All calculations are based on this reactant.

${\mathrm{C}}_{\mathrm{n}}{\mathrm{H}}_{2\mathrm{n}+2(\mathrm{g})}+\frac{3\mathrm{n}+1}{2}{\mathrm{O}}_{2(\mathrm{g})}\to {\mathrm{nCO}}_{2(\mathrm{g})}+(\mathrm{n}+1){\mathrm{H}}_2{\mathrm{O}}_{(\ell )}$

In this case, $100\mathrm{ml}$ of propane is mixed with $700\mathrm{ml}$ of ${\mathrm{O}}_2$.

The balanced chemical equation for the combustion of propane (${\mathrm{C}}_3{\mathrm{H}}_8$) is:

$${\mathrm{C}}_3{\mathrm{H}}_8+5{\mathrm{O}}_2\to 3{\mathrm{CO}}_2+4{\mathrm{H}}_2{\mathrm{O}}_{(\ell )}$$

Given initial volumes: $100\mathrm{ml}$ of ${\mathrm{C}}_3{\mathrm{H}}_8$ and $700\mathrm{ml}$ of ${\mathrm{O}}_2$.

To find the limiting reagent (L.R.):

For ${\mathrm{C}}_3{\mathrm{H}}_8$: $\frac{100}{1}=100$

For ${\mathrm{O}}_2$: $\frac{700}{5}=140$

Since $100$ is the lowest value, ${\mathrm{C}}_3{\mathrm{H}}_8$ acts as the L.R.

Now, let's calculate the amounts after the reaction:

$$\begin{array}{c}{\mathrm{C}}_3{\mathrm{H}}_8+5{\mathrm{O}}_2\to 3{\mathrm{CO}}_2+4{\mathrm{H}}_2{\mathrm{O}}_{(\ell )}\\ 100\mathrm{ml}700\mathrm{ml}\\ -=200\mathrm{ml}300\mathrm{ml}\end{array}$$

This means:

The volume of ${\mathrm{O}}_2$ left is $200\mathrm{ml}$.

The volume of ${\mathrm{CO}}_2$ formed is $300\mathrm{ml}$.

Propane (${\mathrm{C}}_3{\mathrm{H}}_8$) is the limiting reagent.

Final Answer: ${\mathrm{O}}_2$ is the limiting reagent.