500 ml of a hydrocarbon gas is burnt in excess of oxygen yields 2500 ml of CO 2 & 3 litres of water vapours. All volume being measured at the same temperature & pressure. The formula of hydrocarbon

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500 ml of a hydrocarbon gas is burnt in excess of oxygen yields 2500 ml of CO 2 ​ & 3 litres of water vapours. All volume being measured at the same temperature & pressure. The formula of hydrocarbon is :

TestHub · Accepted Answer

The balanced chemical equation for the combustion of a hydrocarbon $C_{x} H_{y}$ is:

$C_{x} H_{y} + O_{2} \to x C O_{2} + \frac{y}{2} H_{2} O$

500 ml excess $↓ 500 x ↓ 250 y$

From the given information, we can set up the following equations:

$500 x = 2500 \Rightarrow x = 5$

$250 y = 3000 \Rightarrow y = 12$

Therefore, the chemical formula is $C_{5} H_{12}$ .

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