Chemistry - Eudiometry Question with Solution | TestHub

Question Explanation: Calculating the volume of a reactant used.

Concept: Stoichiometry and Limiting Reactant.

Solution: Based on the limiting reactant determined in the previous question, we can find the exact volume of oxygen that was consumed in the reaction.

Reaction:

Calculation:

$4N{H}_3(g)+7O_2(g)\to 4N{O}_2(g)+6H_{2}O(l)$

Initial volumes: $20mLN{H}_3$ and $100mL{O}_2$.

$N{H}_3$ identified as the limiting reactant.

The stoichiometric ratio is 4 volumes of $N{H}_3$ to 7 volumes of $O_2$.

Volume of $O_2$ used to completely react with $20mL$ of $N{H}_3$ is:

$$V_{O_2,used}=\frac{7}{4}\times V_{N{H}_3}=\frac{7}{4}\times 20=35mL$$