A hydrocarbon is burnt with just sufficient amount of oxygen. After combustion the volume contraction was 2.5 times of volume of hydrocarbon burnt. On passing this mixture through KOH , if volume cont

Question

A hydrocarbon is burnt with just sufficient amount of oxygen. After combustion the volume contraction was 2.5 times of volume of hydrocarbon burnt. On passing this mixture through KOH , if volume contraction is twice of volume of hydrocarbon taken. Calculate no. of atoms in one molecule of the hydrocarbon.

TestHub · Accepted Answer

C x ​ H y ​ + ( x + 4 y ​ ) O 2 ​ xCO 2 ​ + 2 y ​ H 2 ​ O ( ℓ ) a V ↓ 0 V − a ( x + y /4 ) ax vol contraction = V i ​ − V f ​ = ( a + V ) − [ V − a ( x + 4 y ​ ) + ax ] = a + a 4 y ​ Given that volume contarction = 2.5 V H.C ​ a + a 4 y ​ = 2.5 a ​ y = 6 Given that after passing KOH Vol contraction = 2.0 V H.C ​ a x = 2 a x = 2 ​ H.C C 2 ​ H 6 ​ no. of atom 2 + 6 = 8

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