A 20 mL sample of hydrocarbon C x H y was exploded with excess of O 2 & after the explosion there was a volume contraction of 60 mL . When the resultant mixture is treated with KOH another contr

Question

A 20 mL sample of hydrocarbon C x ​ H y ​ was exploded with excess of O 2 ​ & after the explosion there was a volume contraction of 60 mL . When the resultant mixture is treated with KOH another contraction of 80 mL was observed. Find the value of x + y . Assume all volumes are measured at same pressure and same temperature (25°C).

TestHub · Accepted Answer

C x ​ H y ​ + ( x + 4 y ​ ) O 2 ​ → xCO 2 ​ + 2 y ​ H 2 ​ O 20 mL ( 80 mL ) CO 2 ​ ⇒ 80 mL 20 x = 80 x = 4 Now Let initial volume of O 2 ​ = v 1 ​ volume contraction is given as 60 mL 20 + V 1 ​ − { 80 + [ V 1 ​ − ( x + 4 y ​ ) 20 ] } = 60 − 60 + 80 + 5 y = 60 20 + 5 y = 60 5 y = 40 y = 8

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Doubts & Discussion

JEE Advanced (2028)